The pressure of a sample of dry air is held constant at 2.25 atm while the temperature is decreased rom 100 °C to 7 °C. The original volume of the sample is 43 L. What is the final volume of the sample?

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Answer 1 · 2017-09-14T17:45:02

#V_"final"~=32*L#

We use old Charles' law.......#VpropT# at constant pressure.

#(V_1)/T_1=(V_2)/T_2#

And solve for #V_2=(V_1)/(T_1)xxT_2#

#(43*L)/(373*K)xx280*K=??L#