The region under the curves #y=xe^(x^3), 1<=x<=2# is rotated about the x axis. How do you find the volumes of the two solids of revolution?
1 Answer
May 5, 2017
There is only on solid of revolution generated by this description.
Explanation:
The volume is
Use the substitution
# = [pi/6 e^(2x^3)]_1^2#
# = pi/6(e^16-e^2)#
Use a calculator if you want a decimal approximation.