# The second term of a geometric sequence is 6 and the fifth term is -48. How do you find the tenth term of the sequence?

Dec 29, 2015

First find the common ratio $r$ ...

#### Explanation:

$- \frac{48}{6} = {r}^{\left(5 - 2\right)}$

$r = {\left(- \frac{48}{6}\right)}^{\frac{1}{3}} = - 2$

Tenth Term $= \left(- 48\right) {\left(- 2\right)}^{5} = 1536$

Hope that helped