# The solutions of #y^2+by+c=0# are the reciprocals of the solutions of #x^2-7x+12=0#. Find the value of b + c?

##### 1 Answer

Feb 25, 2017

#### Explanation:

Given:

#x^2-7x+12 = 0#

Divide through by

#1/12-7/12(1/x)+(1/x)^2 = 0#

So putting

#y^2-7/12y+1/12 = 0#

So

#b+c = -7/12+1/12 = -6/12 = -1/2#