# The specific heat of ice is 0.492 cal/(g × °C). How many calories of heat are required to raise 100.0 g of ice from -20.0 °C to -0.5 °C?

##### 2 Answers

Well, your ice DOES NOT undergo a phase change....

#### Explanation:

And so we simply take the product...

#### Explanation:

We use the specific heat equation, which states that,

where:

#q# is the heat energy supplied in joules

#m# is the mass of the substance in kilograms

#c# is the specific heat capacity of the object in joules

#DeltaT# is the change in temperature

Here,

So, we get: