# The sum of 4 consecutive even integers is 132, what are the integers?

May 27, 2015

Suppose the integers are $n$, $n + 2$, $n + 4$ and $n + 6$.

$132 = n + \left(n + 2\right) + \left(n + 4\right) + \left(n + 6\right) = 4 n + 12$

Subtract $12$ from both sides to get:

$4 n = 120$

Divide both sides by $4$ to get:

$n = 30$

So the numbers are:

$30 , 32 , 34 , 36$.