# The sum of three consecutive even integers is 168, what are the integers?

##### 1 Answer
May 30, 2015

If the integers are $n - 2$, $n$ and $n + 2$, then

$168 = \left(n - 2\right) + n + \left(n + 2\right) = 3 n$

Divide both ends by $3$ to get:

$n = 56$

So the three consecutive even integers are $54$, $56$ and $58$,