The sum of three consecutive integers is 915, what are the integers?

May 26, 2015

$304$, $305$ and $306$

To solve this problem you could solve:

$915 = \left(n - 1\right) + n + \left(n + 1\right) = 3 n$

Then divide both sides by $3$ to get $n = 305$.

May 26, 2015

$304 + 305 + 306$

You can write your problem as:

$n + \left(n + 1\right) + \left(n + 2\right) = 915$

$3 n + 3 = 915$

$3 n = 912$

$n = \frac{912}{3} = 304$

so you have

$304 + 305 + 306 = 915$