The temperature off 200.0 mL of a gas originally at STP is changed to -25 degrees at a constant volume. What’s the pressure of gas in atm?

1 Answer
Mar 29, 2018

P_2 = 0.90846 atm

Explanation:

Givens:

P_1 = 1 atm

T_1 = 273.15 K

P_2 =?

T_2 = -25°C+273.15 K= 248.15 K

Use Gay Lussac's Law for pressure and temperature when the volume is constant.

P_1/T_1 = P_2/T_2

"1atm"/"273.15K" = P_2/"248.15K"

0.0036609... = P_2/"248.15K"

0.0036609... x 248.15 K = P_2

P_2 = 0.90846 atm