# The velocity of a particle moving along x - axis is given as #v = x^2 - 5x + 4#(in m/s), where x denotes the x-coordinate of the particle in meters. Find the magnitude of acceleration of the particle when the velocity of particle is zero?

##
A: #0m/s^2#

B: #2m/s^2#

C: #3m/s^2#

D: None of the above

A:

B:

C:

D: None of the above

##### 1 Answer

Aug 8, 2017

A

#### Explanation:

Given velocity

Acceleration

#:.a=d/dt(x^2−5x+4)#

#=>a=(2x(dx)/dt−5(dx)/dt)#

We also know that

#=>a=(2x −5)v#

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