# The volume of a fixed amount of gas is doubled, and the absolute temperature is doubled. According to the ideal gas law, how has the pressure of the gas changed?

Oct 12, 2016

Given that $P = \frac{n R T}{V}$, for an ideal gas, the pressure would be unchanged.
${P}_{1} = \frac{n R T}{V}$
${P}_{2} = \frac{n R \times 2 T}{2 V}$ $=$ $\frac{n R \times \cancel{2} T}{\cancel{2} V}$ $=$ ${P}_{1}$.