# There are three forces acting on an object: 4N to the left, 5N to the right and 3N to the left. What is the net force acting on the object?

Aug 7, 2015

I found: $2 N$ to the left.

#### Explanation:

You have a vectorial composition of your forces:
considering "right" as positive direction you get:

Formally speaking you have the composition of three forces:
${\vec{F}}_{1} = \left(5 N\right) \vec{i}$
${\vec{F}}_{2} = \left(- 3 N\right) \vec{i}$
${\vec{F}}_{3} = \left(- 4 N\right) \vec{i}$
Resultant:
$\Sigma \vec{F} = {\vec{F}}_{1} + {\vec{F}}_{2} + {\vec{F}}_{3} = \left(5 N\right) \vec{i} + \left(- 3 N\right) \vec{i} + \left(- 4 N\right) \vec{i} = \left(- 2 N\right) \vec{i}$ to the left.