Question

Three times the greatest of three consecutive even integers exceeds twice the least by 38. How do you find the integers?

Answer 1

Three integers are `26`, `28` and `30`

Explanation:

Let the even integers be `x`, `x+2` and `x+4`.

As thrice the greatest `x+4` exceeds twice the least `x` by `38`

`3(x+4)-2x=38` or

`3x+12-2x=38` or `3x-2x=38-12`

`x=26`

Hence three integers are `26`, `28` and `30`.