To what temperature does 1.36 L of hydrogen originally at 25.0°C need to be heated in order to bring the volume to 2.5 L?

1 Answer
May 7, 2018

T_2 = ~45.96C

Explanation:

Charles' Law
https://en.wikipedia.org/wiki/Charles%27s_law

(V_1/T_1) = (V_2/T_2)

Plug in your data.

(1.36/25) = (2.5/T_2)

Cross-multiply.

1.36T_2 = 62.5

Divide by 1.36 to isolate for T_2.

62.5/1.36 = T_2

T_2 = 45.95588235294C