Question

To what temperature will a 45.0 g piece of glass rise if it absorbs 6875 joules of heat and its specific heat capacity is 0.50 J/g°C? The initial temperature of the glass is 18.0°C.

Answer 1

I got: `323^@C`

Explanation:

The heat absorbed `Q` is given by:

`Q=mcDeltaT`

with your daata we get:

`6875=45*0.5*(T_f-18)`

rearranging:

`T_f=323^@C`