# To what temperature will a 45.0 g piece of glass rise if it absorbs 6875 joules of heat and its specific heat capacity is 0.50 J/g°C? The initial temperature of the glass is 18.0°C.

May 15, 2018

I got: ${323}^{\circ} C$

#### Explanation:

The heat absorbed $Q$ is given by:

$Q = m c \Delta T$

$6875 = 45 \cdot 0.5 \cdot \left({T}_{f} - 18\right)$
${T}_{f} = {323}^{\circ} C$