# To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C, if the initial temperature of the glass is 20.0°C?

##### 1 Answer

#### Answer:

#### Explanation:

A substance's **specific heat** tells you how much heat much either be *added* or *removed* from **change in temperature**.

The *change in temperature*, **initial temperature** of the sample from the **final temperature** of the sample.

#color(blue)(DeltaT = T_"final" - T_"initial")#

Now, when the substance **absorbs heat**, its temperature will *increase*, which implies that

Your goal here will be to find the *change in temperature* first, then use it to find the final temperature of the sample.

You will have to use this equation

#color(blue)(q = m * c * DeltaT)" "# , where

*change in temperature*

As you can see, this equation establishes a relationship between the amount of heat added or removed from a sample, the mass of that substance, its specific heat, and the resulting change in temperature.

In your case, adding

#q = m * c * DeltaT implies DeltaT = q/(m * c)#

Plug in your values to get

#DeltaT = (5275 color(red)(cancel(color(black)("J"))))/(50.0color(red)(cancel(color(black)("g"))) * 0.50color(red)(cancel(color(black)("J")))/(color(red)(cancel(color(black)("g"))) ""^@"C")) = 211^@"C"#

So, adding that much heat to your sample will result in a

#T_"final" = T_"initial" + DeltaT#

#T_"final" = 20.0^@"C" + 211^@"C" = color(green)(230^@"C")#

The answer is rounded to two sig figs, the number of sig figs you have for the specific heat of glass.