To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C, if the initial temperature of the glass is 20.0°C?
A substance's specific heat tells you how much heat much either be added or removed from
The change in temperature,
#color(blue)(DeltaT = T_"final" - T_"initial")#
Now, when the substance absorbs heat, its temperature will increase, which implies that
Your goal here will be to find the change in temperature first, then use it to find the final temperature of the sample.
You will have to use this equation
#color(blue)(q = m * c * DeltaT)" "#, where
As you can see, this equation establishes a relationship between the amount of heat added or removed from a sample, the mass of that substance, its specific heat, and the resulting change in temperature.
In your case, adding
#q = m * c * DeltaT implies DeltaT = q/(m * c)#
Plug in your values to get
#DeltaT = (5275 color(red)(cancel(color(black)("J"))))/(50.0color(red)(cancel(color(black)("g"))) * 0.50color(red)(cancel(color(black)("J")))/(color(red)(cancel(color(black)("g"))) ""^@"C")) = 211^@"C"#
So, adding that much heat to your sample will result in a
#T_"final" = T_"initial" + DeltaT#
#T_"final" = 20.0^@"C" + 211^@"C" = color(green)(230^@"C")#
The answer is rounded to two sig figs, the number of sig figs you have for the specific heat of glass.