# Train A got from one city to another 45min faster than train B. Train's A speed is 48km/h, train's B speed is 36km/h. What is the distance between the cities?

Mar 23, 2016

I am just writing to clarify what the last contributor had to say.

#### Explanation:

In this problem, we should work with the formula $S = \frac{d}{t}$, where s is speed, d is distance, and t is time.

We can rearrange the formula to $S \times t = d$. Assuming the time it takes train A is x (hours).

$48 \times x = 36 \times \left(x + \frac{3}{4}\right)$

$48 x = 36 x + 27$

$12 x = 27$

$x = \frac{9}{4}$

So, it takes train A $\frac{9}{4}$ hours to travel between the two cities.

Therefore, we can plug in our values into the equation to solve for d: $48 = \frac{d}{\frac{9}{4}}$

$108 = d$

Thus, the distance between the two cities is of 108 kilometres.

Hopefully this helps!