Two bodies are projected at angle theta and 90 minus theta to the horizontal with the same speed the ratio of their horizontal ranges are?

1 Answer
Mar 14, 2018

1:1

Explanation:

Formula for range of a projectile is R=u2sin2θg where,u is the velocity of projection and θ is the angle of projection.

For,u be the same for both the bodies,

R1:R2=sin2θ:sin2(90θ)=sin2θ:sin(1802θ)=sin2θ:sin2θ=1:1 (as, sin(1802θ)=sin2θ)