Two charges of $-1 C$ and $9 C$ are positioned on a line at points $7$ and $-4$ , respectively. What is the net force on a charge of $-3 C$ at $2$ ?

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Answer 1 · 2018-01-17T06:37:12

The net force is $=-5.67*10^9N$

The net force between the charges is

$F=k(Q_1Q_3)/r_1^2+k(Q_2Q_3)/r_2^2$

Where $r$ is the distance between the charges

The Coulomb Constant is $k=9*10^9Nm^2/C^2$

The charge $Q_1=-1C$ at $(7,0)$

The charge $Q_2=9C$ at $(-4,0)$

The charge $Q_3=-3C$ at $(2,0)$

The net force is

$F=910^9*(-1*-3)/(5)^2+910^9(9*-3)/(6)^2=-5.67*10^9N$

The negative sign indicates that the force is attractive

Two charges of -1 C -1 C and 9 C 9 C are positioned on a line at points 7 7 and -4 -4 , respectively. What is the net force on a charge of -3 C -3 C at 2 2 ?