Two charges of # -2 C # and # 3 C# are positioned on a line at points # 5 # and # -6 #, respectively. What is the net force on a charge of # -1 C# at # 0 #?

1 Answer
Feb 12, 2016

Answer:

#F_n=3*10^7#

Explanation:

#F:" force between two charges"#
#F=k*(q_1*q_2)/r^2" Coulomb's law"#
#x:" distance between the charge of 3C and -1C"#
#x=6-0=6 #
#y:" distance between the charge of -1C and -2C"#
#y:5-0=5#
#F_1:" Force between the charge of 3C and -1C"#
#F_1=k*(3*(-1))/6^2#
#F_1=(-3*k)/36#
#F_2:" Force between the charge of -1C and -2C"#
#F_2=(k*(-1)*(-2))/5^2#
#F_2=(2*k)/25#
#F_n=(-3*k)/36+(2*k)/25#
#F_n=(-75*k+72*k)/(36*25)#
#F_n=(-cancel(3)*k)/(cancel(36)*25)#
#F_n=k/(12*25)" , "k=9*10^9#
#F_n=(cancel(9)*10^9)/(cancel(12)*25)" ; "F_n=(3*10^9)/(4*25)#
#F_n=3*10^7#