Question

Two charges of `-2 C` and `3 C` are positioned on a line at points `5` and `-6`, respectively. What is the net force on a charge of `-1 C` at `0`?

Answer 1

`F_n=3*10^7`

Explanation:

`F:" force between two charges"`
`F=k*(q_1*q_2)/r^2" Coulomb's law"`
`x:" distance between the charge of 3C and -1C"`
`x=6-0=6`
`y:" distance between the charge of -1C and -2C"`
`y:5-0=5`
`F_1:" Force between the charge of 3C and -1C"`
`F_1=k*(3*(-1))/6^2`
`F_1=(-3*k)/36`
`F_2:" Force between the charge of -1C and -2C"`
`F_2=(k*(-1)*(-2))/5^2`
`F_2=(2*k)/25`
`F_n=(-3*k)/36+(2*k)/25`
`F_n=(-75*k+72*k)/(36*25)`
`F_n=(-cancel(3)*k)/(cancel(36)*25)`
`F_n=k/(12*25)" , "k=9*10^9`
`F_n=(cancel(9)*10^9)/(cancel(12)*25)" ; "F_n=(3*10^9)/(4*25)`
`F_n=3*10^7`