Two electron are moving towards each other with a velocity of 10^6 m/s what will be the closest distance of approach between them?
1 Answer
Mar 20, 2018
Explanation:
Total kinetic energy of electrons
"K.E" = 2 × 1/2\ "mv"^2
Potential energy of electrons
"U" = ("ke"^2)/"r"
When they approached closest distance (
"K.E = U"
2 × 1/2\ "mv"^2 = ("ke"^2)/"r"
color(blue)["r" = ("ke"^2)/("mv"^2)]