Two electron are moving towards each other with a velocity of 10^6 m/s what will be the closest distance of approach between them?

1 Answer
Mar 20, 2018

"2.53 Å"

Explanation:

Total kinetic energy of electrons

"K.E" = 2 × 1/2\ "mv"^2

Potential energy of electrons

"U" = ("ke"^2)/"r"

When they approached closest distance ("r") their total kinetic energy is converted into potential energy.

"K.E = U"

2 × 1/2\ "mv"^2 = ("ke"^2)/"r"

color(blue)["r" = ("ke"^2)/("mv"^2)]

"r" = (9 × 10^9\ "Nm"^2//"C"^2 × (1.6 × 10^-19\ "C")^2)/(9.1 × 10^-31\ "kg" × (10^6\ "m/s")^2) = 2.53 × 10^-10\ "m" = "2.53 Å"