Question

Two electrons are 1m apart , show that the force beyween them is 2.304 x 10^(-3) ?

Answer 1

`2.304\times10^{-28}\ N`

Explanation:

Force of repulsion (F) between two electrons (each having charge `e=1.6\times10^{-19}\ C`) separated by a distance `r=1\ m` is given as

`F=\frac{1}{4\pi \epsilon_o}\frac{q_1q_2}{r^2}`

`F=9\times10^{9}\cdot \frac{1.6\times10^{-19}\cdot 1.6\times10^{-19}}{1^2}`

`=23.04\times 10^{-29}`

`=2.304\times10^{-28}\ N`