Use Newton's law of Cooling. Can I get some help please? THANKS!
1 Answer
Jan 15, 2018
Explanation:
Start by identifying the parameters.
We know
#52.5 = 0 + (102 - 0)e^(8k)#
#52.5 = 102e^(8k)#
#0.5147 = e^(8k)#
#ln(0.5147) = ln(e^(8k))#
#ln(0.5147) = 8k#
#k = -0.083#
Now we're going to solve for
#T = 0 + (102 - 0)e^(13(-0.083))#
#T = 34.67˚F#
To the nearest degree,
Hopefully this helps!