The answer will be negative.
Writing down a few multiples of #35# first helps the division process.
#35: 35," "70," ", 105," " 140," " 175, " "210...#
#color(white)(............................)-color(red)(3)color(blue)(.6)#
#color(white)(.......................)35)bar126.00color(white)(...................) larr126div35= color(red)(3)#
#color(white)(..............................)ul105color(white)(.......................)larr color(red)(3)xx35=105#
#color(white)(...............................)210color(white)(.....................)larr# subtract, add 0
#color(white)(...............................)ul210color(white)(..........................)210div35=color(blue)(6)#
