# Using the ideal gas formula, calculate the volume of 1.50 moles of a gas at 115 kPA and a temperature of 298K?

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using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?

using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?

##### 1 Answer

#### Explanation:

This is a pretty straightforward **ideal gas law** equation practice problem, so make sure that you're familiar with the aforementioned ideal gas law equation

#color(blue)(|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)|)))" "# , where

*universal gas constant*, usually given as

**absolute temperature** of the gas

Now, the most important thing to do at this point is make sure that the **units** given to you **match** those used in the expression of the ideal gas constant.

As you can see, the *pressure* of the gas is given to you in *kPa*, but you actually need it to be expressed in *atm*. This means that you're going to have to convert it by using the conversion factor

#color(purple)(|bar(ul(color(white)(a/a)color(black)("1 atm " = " 101.325 kPa")color(white)(a/a)|)))#

Rearrange the ideal gas law equation to solve for

#PV = nRT implies V = (nRT)/V#

Plug in your values to get

#V = (1.50color(red)(cancel(color(black)("moles"))) * 0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 298color(red)(cancel(color(black)("K"))))/(115/101.325color(red)(cancel(color(black)("atm")))) = color(green)(|bar(ul(color(white)(a/a)"32.3 L"color(white)(a/a)|)))#

The answer is rounded to three **sig figs**.