Verify the change in oxidation number.......2Cu2O(s)+Cu2S(s)---6Cu (s)+SO2(s)?

1 Answer
Mar 28, 2018

Here's what I get.

Explanation:

The oxidation numbers

The oxidation numbers of the atoms in the equation are

#stackrelcolor(blue)("+1")("Cu")_2stackrelcolor(blue)("-2")("O") + stackrelcolor(blue)("+1")("Cu")_2stackrelcolor(blue)("-2")("S") → stackrelcolor(blue)(0)("Cu") + stackrelcolor(blue)("+4")("S")stackrelcolor(blue)("-2")("O")_2#

Changes in oxidation number

#"Cu"# in #"Cu"_2"O"#: Changes from +1 to 0, Change = -1.
#"Cu"# in #"Cu"_2"S"color(white)(l)#: Changes from +1 to 0, Change = -1.
#"S"# in #"Cu"_2"S"color(white)(m)#: Changes from -2 to +4, Change = +6