# What amount of heat is needed to raise 27.0 g of water from 10.0 °C to 90.0 °C?

Jun 4, 2014

The heat needed is 9.04 kJ.

The formula to use is

q = mcΔT

where $q$ is the heat, $m$ is the mass, $c$ is the specific heat capacity, and ΔT is the temperature change.

$m$ = 27.0 g; $c$ = 4.184 J·°C⁻¹g⁻¹; ΔT = T_2 - T_1 = (90.0 – 10.0) °C = 80.0°C

q = mcΔT = 27.0 g × 4.184 J·°C⁻¹g⁻¹ × 80.0 °C = 9040 J = 9.04 kJ