What applied force is needed by a 5kg to accelerate 10 m/s2?

2 Answers
Jun 26, 2018

Answer:

#F_"net" = 50 N#

Explanation:

Newton's 2nd Law says that

#F_"net" = m*a#

So, plugging in your data, #F_"net" = 5 kg*10 m/s^2 = 50 (kg*m)/s^2#

So the answer is #F_"net" = 50 N#.

I hope this helps,
Steve

Jun 27, 2018

Answer:

#50# newtons

Explanation:

We use Newton's second law of motion, which states that,

#F=ma#

where:

  • #F# is the net force applied in newtons

  • #m# is the mass of the object in kilograms

  • #a# is the acceleration of the object in meters per second squared

So, we get:

#F=5 \ "kg"*10 \ "m/s"^2#

#=50 \ "N" \ (because 1 \ "N"-=1 \ "kg m/s"^2)#