# What applied force is needed by a 5kg to accelerate 10 m/s2?

Jun 26, 2018

${F}_{\text{net}} = 50 N$

#### Explanation:

Newton's 2nd Law says that

${F}_{\text{net}} = m \cdot a$

So, plugging in your data, ${F}_{\text{net}} = 5 k g \cdot 10 \frac{m}{s} ^ 2 = 50 \frac{k g \cdot m}{s} ^ 2$

So the answer is ${F}_{\text{net}} = 50 N$.

I hope this helps,
Steve

Jun 27, 2018

$50$ newtons

#### Explanation:

We use Newton's second law of motion, which states that,

$F = m a$

where:

• $F$ is the net force applied in newtons

• $m$ is the mass of the object in kilograms

• $a$ is the acceleration of the object in meters per second squared

So, we get:

$F = 5 \setminus {\text{kg"*10 \ "m/s}}^{2}$

=50 \ "N" \ (because 1 \ "N"-=1 \ "kg m/s"^2)