Question

What are the 6 trig ratios given a right triangle ABC with sides a = 4, b = 10?

Answer 1

Pythagoras Theorem -> c^2 = a^2 + b^2 = 16 + 100 = 116

c = 10.77

sin A = 4/10.77 = 0.37
cos A = 10/10.77 = 0.93
tan A = 0.37/0.93 = 0.40
sin B = 10.10,77 = 0.93 = cos A
cos B = 4/10.77 = 0.37 = sin A
tan B = 0.93/0.37 = 2.50 = cot A