What are the asymptote(s) and hole(s), if any, of $f(x) =(1+1/x)/((x-3)*x)$ ?

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Answer 1 · 2018-05-20T17:04:35

No holes, $x = 0 and x =3$ are the asymptotes.

There are no factors that cancel out in the numerator and denominator so there are no holes.

To find the asymptotes we set the denominator equal to 0 and solve for where the function is undefined.

$(x-3) * x =0$

$x = 0 and x =3$ are the asymptotes.

What are the asymptote(s) and hole(s), if any, of f(x) =(1+1/x)/((x-3)*x) f(x) =(1+1/x)/((x-3)*x)?