# What are the asymptote(s) and hole(s), if any, of # f(x) =1/(e^x-2)#?

##### 1 Answer

Jun 13, 2018

There is a asymptote at

#### Explanation:

There are no holes because no factors will cancel out of the numerator and denominator, the asymptote(s) are when we have

graph{1/(e^x-2) [-10, 10, -5, 5]}