# What are the asymptote(s) and hole(s), if any, of # f(x) =1/x^2-1/(1-x)+x/(3-x)#?

##### 1 Answer

Apr 9, 2018

Vertical asymptotes at

#### Explanation:

Asymptotes and holes are present due to the fact that the denominator of any fraction cannot be 0, since division by zero is impossible.

Since there are no cancelling factors, the non permissible values are all vertical asymptotes.

Therefore:

and

and

Which is all the vertical asymptotes.