# What are the asymptote(s) and hole(s), if any, of # f(x) =(-2x^2-6x)/((x-3)(x+3)) #?

##### 1 Answer

Asymptotes at

#### Explanation:

We have

Which we can write as:

Which reduces to:

You find the vertical asymptote of

So here,

For the horizontal asymptote, there exists three rules:

To find the horizontal asymptotes, we must look at the degree of the numerator (

If

If

If

Here, since the degree of the numerator is

The hole is at

This is because our denominator had

A graph confirms this:

graph{(-2x^2-6x)/((x+3)(x-3)) [-12.29, 13.02, -7.44, 5.22]}