# What are the asymptote(s) and hole(s), if any, of  f(x) =(xln2)/(e^x-2)?

Feb 15, 2018

VA is $\ln 2$, no holes

#### Explanation:

To find the asymptote, find any restrictions in the equation. In this question, the denominator can not be equal to 0. this means that whatever x is equal to will be undefined in our graph

${e}^{x} - 2 = 0$
${e}^{x} = 2$
${\log}_{e} \left(2\right) = x$

Your asymptote is $x = {\log}_{e} \left(2\right)$ or $\ln 2$ which is a VA