# What are the asymptotes for (x-3) / (x-2) ?

Aug 8, 2015

#### Answer:

There is a vertical asymptote at $\textcolor{red}{x = 2}$ and a horizontal asymptote at $\textcolor{red}{y = 1}$.

#### Explanation:

$y = \frac{x - 3}{x - 2}$

Step 1. Find the vertical asymptotes.

Set the denominator equal to zero and solve for $x$.

$x - 2 = 0$

$x = 2$

There is a vertical asymptote at $x = 2$.

Step 2. Find the horizontal asymptotes.

We divide the coefficients of the highest terms.

$\frac{1}{1} = 1$

The horizontal asymptote is at $y = 1$.