Question

What are the asymptotes of `y=1/(x+3)` and how do you graph the function?

Answer 1

Vertical: `uarrx--3darr`
Horizontal: `larry = 0rarr`

Explanation:

graph{y(x+3)-1=0 [-10, 10, -5, 5]} `y = 1/(x+3) to +-oo, as x to 3`

Inversely,

x 1/y-3 to +-oo, as x to 0#.

So, the asynptotes are x = -3 and y = 0.

Interestingly, the equation `y(x+3=1` represents the rectangular

hyperbola, having these asymptotes that meet at its center (-3, 0).