# What are the critical points of #f(x) = x^2 + 2/x#?

##### 1 Answer

Dec 2, 2016

#### Answer:

#### Explanation:

The critical points will occur when the derivative equals

#f'(x) = 2x + (0 xx x - 1 xx 2)/(x)^2#

#f'(x) = 2x - 2/x^2#

The derivative will be undefined at **not** a critical point.

#0 = 2x - 2/x^2#

#0 = (2x^3 - 2)/x^2#

#0 = 2x^3 - 2#

#2 = 2x^3#

#1= x^3#

#x = 1#

The corresponding y-coordinate is

#f(1) = 1^2 + 2/1 = 3#

Hence, the only critical point is at

Hopefully this helps!