What are the critical points of g(x)=(x+2)/(7-4x)?

1 Answer
Dec 20, 2016

g(x) has no critical point and is strictly increasing in its domain.

Explanation:

Critical points are determined as the values of x for which the first derivative vanishes, so:

g'(x) = frac ((7-4x)+4(x+2)) ((7-4x)^2)=15/((7-4x)^2)

Evidently, the derivative of g(x)is always positive and never equals zero, thus g(x) has no critical point and is strictly increasing in its domain.

graph{(x+2)/(7-4x) [-10, 10, -5, 5]}