What are the critical values, if any, of #f(x)=2x^3 - 54x^2 + 480x - 1300#?

1 Answer
Dec 9, 2016

Start by finding the derivative.

#f'(x) = 6x^2 - 108x + 480#

#f'(x) = 6(x^2 - 18x + 80)#

#f'(x) = 6(x - 10)(x - 8)#

The critical values occur when #f'(x) = 0# or is undefined.

There will be no undefined points in this function, so we set this to #0# and solve.

#0 = 6(x - 10)(x - 8)#

#x = 10 and 8#

Therefore, the critical values are #x = 10# and #x = 8#.