What are the domain and range of the function?

f(x)=2^x+1

1 Answer
Jul 19, 2017

Domain is #(-oo,oo)# and range is #(1,oo)#

Explanation:

As #2^x# is defined for all values of #x#,

domain is #x inRR -> (-oo,oo)#

However for #x->-oo# #f(x)=2^x+1=0+1=1#

and for #x->oo# #f(x)=2^x+1->oo#

Hence range is #(1,oo)#

graph{2^x+1 [-26.92, 13.08, -0.96, 19.04]}