What are the exact solutions of #x^2 − 3x − 7 = 0#?

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Answer 1 · 2016-11-13T14:02:56

4.54 and -1.54

#x^2-3x-7=0#

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Here

#a=+1#

#b=-3#

#c=-7#

#x={-(-3)+-sqrt[(-3)^2-4times(1)times(-7)]}/(2times(-1))#

After solving we get

#x={3+sqrt(37)}/(2)# and #x={3-sqrt(37)}/2#

Therefore #x=4.54 and x=-1.54#