What are the excluded values for the rational expression #(3m)/(m^2-6m+5)#?

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Answer 1 · 2017-07-03T16:24:38

See a solution process below:

We cannot divide by #0#, therefore the excluded values can be written as:

#m^2 - 6m + 5 != 0#

Factoring gives:

#(m - 5)(m - 1) != 0#

Solving each term for #0# will give the values of #m# which are excluded:

Solution 1)

#m - 5 != 0#

#m - 5 + color(red)(5) != 0 + color(red)(5)#

#m - 0 != 5#

#m != 5#

Solution 1)

#m - 1 != 0#

#m - 1 + color(red)(1) != 0 + color(red)(1)#

#m - 0 != 1#

#m != 1#

The excluded values are: #m != 5# and #m != 1#