What are the excluded values for #y=x/(x+2)#?

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Answer 1 · 2018-01-05T01:45:11

See a solution process below:

We cannot divide by zero. Therefore the excluded value would be:

#x + 2 != 0#

Or

#x + 2 - color(red)(2) != 0 - color(red)(2)#

#x + 0 != -2#

#x != -2#

The Excluded Value Is: #-2#