What are the extrema of #f(x) = 1 - sqrt(x)#?

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Answer 1 · 2016-12-08T10:51:45

Max f = 1. There is no minimum.

#y=f(x)=1-sqrtx#. Graph is inserted.

This represents a semi parabola, in the quadrants #Q_1 and Q_4#,

wherein x >=0.

Max y is at the end (0, 1). Of course, there is no minimum.

Note that, as #x to oo, y to -oo#.

The parent equation is #(y-1)^2 = x# that can be separated into

#y=1+-sqrtx#.

graph{y+sqrtx-1=0 [-2.5, 2.5, -1.25, 1.25]}