What are the extrema of #f(x) = 8 - 2x# for #x>=6#? Calculus Graphing with the First Derivative Identifying Turning Points (Local Extrema) for a Function 1 Answer Anjali G Nov 13, 2016 #f(x)# is a line with a negative slope, so on the interval #x>= 6#, the maximum is at #x=6#. There is no minimum because #f(x)# is always decreasing, and the interval given is #[6,oo]#. graph{-2x+8 [-4.25, 15.75, -7.8, 2.2]} Answer link Related questions How do you find the x coordinates of the turning points of the function? How do you find the turning points of a cubic function? How many turning points can a cubic function have? How do you find the coordinates of the local extrema of the function? How do you find the local extrema of a function? How many local extrema can a cubic function have? How do I find the maximum and minimum values of the function #f(x) = x - 2 sin (x)# on the... If #f(x)=(x^2+36)/(2x), 1 <=x<=12#, at what point is f(x) at a minimum? How do you find the maximum of #f(x) = 2sin(x^2)#? How do you find a local minimum of a graph using the first derivative? See all questions in Identifying Turning Points (Local Extrema) for a Function Impact of this question 1612 views around the world You can reuse this answer Creative Commons License