# What are the extrema of f(x)=f(x)= x^2 -4x +3?

Jan 21, 2016

The extrema is at x = 2; obtained by solving $f ' \left(x\right) = 0$
$f ' \left(x\right) = 2 x - 4 = 0$; Take a look at the graph it will help.
Given f(x) = x^2 - 4x + 3; f'(x) = 2x -4; f'' = 2 constant
Now set $f ' \left(x\right) = 0$ and solve for ==> $x = 2$