What are the extrema of #g(x) = 2 sin(2x - pi) + 4# on #[-pi/2,pi/2]#?

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Answer 1 · 2018-05-27T07:04:15

#x=+-pi/4# for #x in[-pi/2,pi/2]#

#g(x) =2sin(2x-pi)+4#

#g(x) =-2sin(2x)+4#

For extrema of #g(x)#, #g'(x)=0#

#g'(x) =-4cos(2x)#

#g'(x)=0#

#-4cos(2x)=0#

#cos(2x)=0#

#2x=+-pi/2#

#x=+-pi/4# for #x in[-pi/2,pi/2]#