# What are the intercepts of y=-2(x+3)^2+25?

Y-intercept is at (0,7) ; X-intercepts are at $\left(\frac{5}{\sqrt{2}} - 3 , 0\right) \mathmr{and} \left(- \frac{5}{\sqrt{2}} - 3 , 0\right)$
Y-intercept: putting x=0 in the equation we get $y = - 2 \cdot 9 + 25 = 7$ So Y-intercept is at (0,7); X-ntercept : putting y=0 in the equation we get $2 {\left(x + 3\right)}^{2} = 25 \mathmr{and} {\left(x + 3\right)}^{2} = \frac{25}{2} \mathmr{and} x + 3 = \frac{5}{\sqrt{2}} \mathmr{and} x + 3 = - \frac{5}{\sqrt{2}} \mathmr{and} x = - 3 + \frac{5}{\sqrt{2}} \mathmr{and} x = - 3 - \frac{5}{\sqrt{2}}$ graph{-2(x+3)^2+25 [-80, 80, -40, 40]}[Ans]