Question

What are the local extrema, if any, of `f (x) =x/(-12x+2`?

Answer 1

`f'(x)=2/(-12x+2)^2 ne0` so no extrema

Explanation:

By the Quotient rule we get

`f'(x)=(-12x+2-x(-12))/(-12x+2)^2`

`f'(x)=2/(-12x+2)^2`