# What are the mean and standard deviation of a binomial probability distribution with n=777  and p=19/21 ?

Mean = np = $777 \cdot \frac{19}{21}$ = 703
Variance = np(1-p) = $777 \cdot \frac{19}{21} \cdot \frac{2}{21}$ = 66.952...
Standard Deviation = $\sqrt{v a r i a n c e}$ = 8.18 (3sf)